通过实例简要介绍case函数的用法。    
1.创建测试表:    DROP SEQUENCE student_sequence;
  CREATE SEQUENCE student_sequence START WITH 10000 INCREMENT BY 1;  
  DROP TABLE students;
  CREATE TABLE students (
  id        NUMBER(5) PRIMARY KEY,
  first_name    VARCHAR2(20),
  last_name    VARCHAR2(20),
  major      VARCHAR2(30),
  current_credits NUMBER(3),
  grade      varchar2(2));  
  INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Scott', 'Smith', 'Computer Science', 98,null);  
  INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Margaret', 'Mason', 'History', 88,null);  
  INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Joanne', 'Junebug', 'Computer Science', 75,null);  
  INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Manish', 'Murgratroid', 'Economics', 66,null);  
  commit;    
2.查看相应数据    SQL> select * from students;  
  ID    FIRST_NAME    LAST_NAME      MAJOR    CURRENT_CREDITS  GR
  ------  ----------------- ------------------- ----------- ----------------- -----
  10000  Scott        Smith       Computer Science      98
  10001  Margaret       Mason       History          88
  10002  Joanne        Junebug      Computer Science      75
  10003  Manish       Murgratroid     Economics         66    
3.更新语句    update students
  set grade = (
  select grade from
  (
  select id,
  case when current_credits > 90 then 'a'
  when current_credits > 80 then 'b'
  when current_credits > 70 then 'c'
  else 'd' end grade
  from students
  ) a
  where a.id = students.id
  )
  /    
4.更新后结果    SQL> select * from students;  
  ID FIRST_NAME  LAST_NAME      MAJOR         CURRENT_CREDITS GR
  ------------- ---------------- -------------------- ---------------------------- ----
  10000 Scott    Smith      Computer Science              98 a
  10001 Margaret  Mason      History                   88 b
  10002 Joanne   Junebug     Computer Science              75 c
  10003 Manish   Murgratroid   Economics                  66 d 
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